20 lines
652 B
Python
20 lines
652 B
Python
from utils import get, init_table, print_table
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def longest_common_substring(a, b):
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"""
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Computes the length of the longest string that's present in both `a` and
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`b`.
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"""
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table = init_table(rows=len(b), cols=len(a), default=0)
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for row in range(len(table)):
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for col in range(len(table[row])):
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if b[row] == a[col]:
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table[row][col] = 1 + get(table, row - 1, col - 1)
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return max([max(row) for row in table])
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dictionary = ["fish", "vista"]
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result = [longest_common_substring("hish", x) for x in dictionary]
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expected = [3, 2]
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print(result, expected)
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assert result == expected
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print("Success!")
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