aa66d9b83d
Add attempts at solving coding problems to Briefcase.
42 lines
1.2 KiB
Python
42 lines
1.2 KiB
Python
from utils import get, init_table, print_table
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# This problem has a few variants:
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# - limited supply of each item
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# - unlimited supply of each item
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# - fractional amounts of each item (e.g. rice)
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def max_haul(capacity, items):
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min_kg = min([kg for _, kg in items])
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max_kg = max([kg for _, kg in items])
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cols = int(max_kg / min_kg)
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fr_col_index = lambda index: min_kg * index + min_kg
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to_col_index = lambda capacity: int((capacity - min_kg) * cols / max_kg)
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table = init_table(rows=len(items), cols=cols, default=0)
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for row in range(len(table)):
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for col in range(len(table[row])):
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curr_capacity = fr_col_index(col)
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value, kg = items[row]
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if kg > curr_capacity:
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a = 0
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else:
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a = value + get(table, row - 1, to_col_index(curr_capacity - kg))
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b = get(table, row - 1, col)
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table[row][col] = max([a, b])
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print_table(table)
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return table[-1][-1]
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guitar = (1500, 1)
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stereo = (3000, 4)
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laptop = (2000, 3)
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necklace = (2000, 0.5)
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items = [necklace, guitar, stereo, laptop]
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capacity = 4
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result = max_haul(capacity, items)
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expected = 4000
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print(result, expected)
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assert result == expected
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print("Success!")
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