tvl-depot/scratch/facebook/highest-product-of-3.py
William Carroll aa66d9b83d Add coding exercises for Facebook interviews
Add attempts at solving coding problems to Briefcase.
2020-11-12 14:37:29 +00:00

20 lines
689 B
Python

def hi_product(xs):
lowest_one, highest_one = min(xs[0], xs[1]), max(xs[0], xs[1])
lowest_two, highest_two = xs[0] * xs[1], xs[0] * xs[1]
highest = float('-inf')
for x in xs[2:]:
highest = max(highest, highest_two * x, lowest_two * x)
lowest_one = min(lowest_one, x)
highest_one = max(highest_one, x)
lowest_two = min(lowest_two, highest_one * x, lowest_one * x)
highest_two = max(highest_two, highest_one * x, lowest_one * x)
return highest
xs = [([-10,-10,1,3,2], 300),
([1,10,-5,1,-100], 5000)]
for x, expected in xs:
result = hi_product(x)
print(x, result)
assert result == expected
print("Success!")