019f8fd211
git-subtree-dir: users/wpcarro git-subtree-mainline:464bbcb15cgit-subtree-split:24f5a642afChange-Id: I6105b3762b79126b3488359c95978cadb3efa789
42 lines
1.3 KiB
Python
42 lines
1.3 KiB
Python
from utils import get, init_table, print_table
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def optimal_itinerary(duration, items):
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min_duration = min([duration for duration, _ in items])
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max_duration = max([duration for duration, _ in items])
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table = init_table(rows=len(items), cols=int(max_duration / min_duration), default=0)
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to_index = lambda duration: int(duration / min_duration) - 1
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to_duration = lambda i: i * min_duration + min_duration
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for row in range(len(table)):
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for col in range(len(table[row])):
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curr_duration = to_duration(col)
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duration, value = items[row]
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if duration > curr_duration:
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a = 0
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else:
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a = value + get(table, row - 1, to_index(curr_duration - duration))
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b = get(table, row - 1, col)
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table[row][col] = max([a, b])
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print_table(table)
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return table[-1][-1]
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# You're in London for two days, and you'd like to see the following
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# attractions. How can you maximize your time spent in London?
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westminster = (0.5, 7)
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globe_theater = (0.5, 6)
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national_gallery = (1, 9)
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british_museum = (2, 9)
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st_pauls_cathedral = (0.5, 8)
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items = [
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westminster,
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globe_theater,
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national_gallery,
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british_museum,
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st_pauls_cathedral,
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]
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result = optimal_itinerary(2, items)
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expected = 24
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print(result, expected)
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assert result == expected
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print("Success!")
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