aa66d9b83d
Add attempts at solving coding problems to Briefcase.
94 lines
2.3 KiB
Python
94 lines
2.3 KiB
Python
# This is a scratch pad for randomly selected questions
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# def char_and_rest(i, xs):
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# return xs[i], xs[:i] + xs[i+1:]
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# def perms(xs):
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# if len(xs) == 1:
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# return [xs]
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# result = []
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# for i in range(len(xs)):
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# c, rest = char_and_rest(i, xs)
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# for perm in perms(rest):
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# result.append(c + ''.join(perm))
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# return result
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# print(perms(list("woah")))
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# def f(take_out, dine_in, served):
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# j, k = 0, 0
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# for i in range(len(served)):
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# if j < len(take_out) and served[i] == take_out[j]:
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# j += 1
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# elif k < len(dine_in) and served[i] == dine_in[k]:
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# k += 1
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# else:
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# return False
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# if j < len(take_out) or k < len(dine_in):
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# return False
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# return True
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# take_out = [17, 8, 24]
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# dine_in = [12, 19, 2]
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# served = [17, 8, 12, 19, 24, 2]
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# print(f(take_out, dine_in, served))
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# def match(a, b):
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# if a == '{':
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# return b == '}'
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# if a == '[':
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# return b == ']'
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# if a == '(':
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# return b == ')'
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# return False
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# def f(xs):
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# s = []
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# for c in xs:
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# if c in {'{', '[', '('}:
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# s.append(c)
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# elif c in {'}', ']', ')'}:
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# opener = s.pop()
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# if not match(opener, c):
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# return False
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# return len(s) == 0
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# assert f("{[]()}")
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# assert f("{[(])}") == False
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# assert f("{[}") == False
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# print("Success!")
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# def valid_bst(node):
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# lhs = max_bst_value(node.left) if node.left else float('-inf')
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# rhs = min_bst_value(node.right) if node.right else float('inf')
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# return and([
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# lhs <= node.value,
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# rhs > node.value,
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# valid_bst(node.left),
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# valid_bst(node.right),
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# ])
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import random
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import math
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def shuffle(xs):
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n = len(xs)
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for i in range(n - 1):
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j = random.randint(i + 1, n - 1)
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xs[i], xs[j] = xs[j], xs[i]
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return xs
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def as_card(i):
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if i not in range(1, 53):
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raise Exception("Not a card")
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# 1
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suit = ['Hearts', 'Clubs', 'Diamonds', 'Spades'][math.floor((i - 1) / 13)]
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n = ['Ace',2,3,4,5,6,7,8,9,10,'Jack','Queen','King'][(i - 1) % 13]
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return '{} of {}'.format(n, suit)
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xs = list(range(1, 53))
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print(xs)
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shuffle(xs)
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for x in xs:
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print(as_card(x))
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