Implement a simple hash function and hash table

I was always curious how hashing functions were implemented, so I read about the
"polynomial rolling hash function", and I decided implementing it would be a
good exercise. After writing that, writing a hash table was simple.
This commit is contained in:
William Carroll 2020-11-16 00:35:01 +00:00
parent 363519273a
commit 30f4d6f4a4

View file

@ -0,0 +1,59 @@
def compute_hash(x):
"""
Compute a unique fingerprint for the string input, `x`, as an integer using
the following equation:
x[0] * P^0 + x[1] * P^1 + ... x[n-1] * P^(n-1) % M
P and M are constants.
"""
p = 31 # small prime number
m = int(10e9) + 9 # large prime number
power = 0
result = 0
for c in x:
result += ord(c) * p**power
power += 1
return result % m
class HashTable(object):
def __init__(self, size):
buckets = []
for _ in range(size):
buckets.append([])
self.xs = buckets
self.compute_hash = lambda k: compute_hash(k) % size
def __repr__(self):
result = []
for bucket in self.xs:
for entry in bucket:
result.append(entry)
return "HashTable({})".format(",".join(str(x) for x in result))
def get(self, key):
"""
Attempt to retrieve value stored under `key`.
"""
h = self.compute_hash(key)
for k, v in self.xs[h]:
if k == key:
return v
return None
def put(self, key, val):
"""
Set `key` to `val`; update value at `key` if it already exists.
"""
h = self.compute_hash(key)
for i in range(len(self.xs[h])):
# Update entry if the key exists...
if self.xs[h][i][0] == key:
self.xs[h][i] = (key, val)
return None
# ...create a new entry otherwise
self.xs[h].append((key, val))
def delete(self, key):
h = self.compute_hash(key)
self.xs[h] = list(filter(lambda entry: entry[0] != key, self.xs[h]))