Solve InterviewCake's recursive string permutations problem
Write a function that returns the set of all of the possible permutations of an input string. This function should be solved recursively.
This commit is contained in:
parent
062af32e4e
commit
2f817e4dd7
2 changed files with 86 additions and 1 deletions
85
scratch/deepmind/part_two/recursive-string-permutations.ts
Normal file
85
scratch/deepmind/part_two/recursive-string-permutations.ts
Normal file
|
@ -0,0 +1,85 @@
|
|||
// Returns a new string comprised of every characters in `xs` except for the
|
||||
// character at `i`.
|
||||
function everyOtherChar(xs: string, i: number): string[] {
|
||||
const result = [];
|
||||
|
||||
for (let j = 0; j < xs.length; j += 1) {
|
||||
if (i !== j) {
|
||||
result.push(xs[j]);
|
||||
}
|
||||
}
|
||||
|
||||
return [xs[i], result.join('')];
|
||||
}
|
||||
|
||||
function getPermutations(xs: string): Set<string> {
|
||||
if (xs === '') {
|
||||
return new Set(['']);
|
||||
}
|
||||
|
||||
const result: Set<string> = new Set;
|
||||
|
||||
for (let i = 0; i < xs.length; i += 1) {
|
||||
const [char, rest] = everyOtherChar(xs, i);
|
||||
const perms = getPermutations(rest);
|
||||
|
||||
for (const perm of perms) {
|
||||
result.add(char + perm);
|
||||
}
|
||||
}
|
||||
|
||||
return result;
|
||||
}
|
||||
|
||||
// Tests
|
||||
let desc = 'empty string';
|
||||
let input = '';
|
||||
let actual = getPermutations(input);
|
||||
let expected = new Set(['']);
|
||||
assert(isSetsEqual(actual, expected), desc);
|
||||
|
||||
desc = 'one character string';
|
||||
input = 'a';
|
||||
actual = getPermutations(input);
|
||||
expected = new Set(['a']);
|
||||
assert(isSetsEqual(actual, expected), desc);
|
||||
|
||||
desc = 'two character string';
|
||||
input = 'ab';
|
||||
actual = getPermutations(input);
|
||||
expected = new Set(['ab', 'ba']);
|
||||
assert(isSetsEqual(actual, expected), desc);
|
||||
|
||||
desc = 'three character string';
|
||||
input = 'abc';
|
||||
actual = getPermutations(input);
|
||||
expected = new Set(['abc', 'acb', 'bac', 'bca', 'cab', 'cba']);
|
||||
assert(isSetsEqual(actual, expected), desc);
|
||||
|
||||
desc = 'four character string';
|
||||
input = 'abca';
|
||||
actual = getPermutations(input);
|
||||
expected = new Set([
|
||||
'abca', 'abac', 'acba', 'acab', 'aabc', 'aacb', 'baca', 'baac', 'bcaa',
|
||||
'bcaa', 'baac', 'baca', 'caba', 'caab', 'cbaa', 'cbaa', 'caab', 'caba',
|
||||
'aabc', 'aacb', 'abac', 'abca', 'acab', 'acba'
|
||||
]);
|
||||
assert(isSetsEqual(actual, expected), desc);
|
||||
|
||||
function isSetsEqual(as, bs) {
|
||||
if (as.size !== bs.size) {
|
||||
return false;
|
||||
}
|
||||
for (let a of as) {
|
||||
if (!bs.has(a)) return false;
|
||||
}
|
||||
return true;
|
||||
}
|
||||
|
||||
function assert(condition, desc) {
|
||||
if (condition) {
|
||||
console.log(`${desc} ... PASS`);
|
||||
} else {
|
||||
console.log(`${desc} ... FAIL`);
|
||||
}
|
||||
}
|
|
@ -28,7 +28,7 @@
|
|||
** DONE MeshMessage
|
||||
** DONE Find Repeat, Space Edition BEAST MODE
|
||||
* Dynamic programming and recursion
|
||||
** TODO Recursive String Permutations
|
||||
** DONE Recursive String Permutations
|
||||
** TODO Compute nth Fibonacci Number
|
||||
** TODO Making Change
|
||||
** TODO The Cake Thief
|
||||
|
|
Loading…
Reference in a new issue