2020-01-12 00:36:56 +01:00
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Rerere
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This document describes the rerere logic.
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Conflict normalization
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----------------------
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To ensure recorded conflict resolutions can be looked up in the rerere
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database, even when branches are merged in a different order,
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different branches are merged that result in the same conflict, or
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when different conflict style settings are used, rerere normalizes the
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conflicts before writing them to the rerere database.
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Different conflict styles and branch names are normalized by stripping
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the labels from the conflict markers, and removing the common ancestor
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version from the `diff3` conflict style. Branches that are merged
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in different order are normalized by sorting the conflict hunks. More
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on each of those steps in the following sections.
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Once these two normalization operations are applied, a conflict ID is
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calculated based on the normalized conflict, which is later used by
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rerere to look up the conflict in the rerere database.
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Removing the common ancestor version
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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Say we have three branches AB, AC and AC2. The common ancestor of
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these branches has a file with a line containing the string "A" (for
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brevity this is called "line A" in the rest of the document). In
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branch AB this line is changed to "B", in AC, this line is changed to
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"C", and branch AC2 is forked off of AC, after the line was changed to
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"C".
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Forking a branch ABAC off of branch AB and then merging AC into it, we
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get a conflict like the following:
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<<<<<<< HEAD
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B
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=======
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C
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>>>>>>> AC
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Doing the analogous with AC2 (forking a branch ABAC2 off of branch AB
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and then merging branch AC2 into it), using the diff3 conflict style,
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we get a conflict like the following:
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<<<<<<< HEAD
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B
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||||||| merged common ancestors
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A
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=======
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C
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>>>>>>> AC2
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By resolving this conflict, to leave line D, the user declares:
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After examining what branches AB and AC did, I believe that making
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line A into line D is the best thing to do that is compatible with
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what AB and AC wanted to do.
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As branch AC2 refers to the same commit as AC, the above implies that
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this is also compatible what AB and AC2 wanted to do.
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By extension, this means that rerere should recognize that the above
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conflicts are the same. To do this, the labels on the conflict
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markers are stripped, and the common ancestor version is removed. The above
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examples would both result in the following normalized conflict:
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<<<<<<<
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B
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=======
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C
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>>>>>>>
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Sorting hunks
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~~~~~~~~~~~~~
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As before, lets imagine that a common ancestor had a file with line A
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its early part, and line X in its late part. And then four branches
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are forked that do these things:
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- AB: changes A to B
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- AC: changes A to C
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- XY: changes X to Y
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- XZ: changes X to Z
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Now, forking a branch ABAC off of branch AB and then merging AC into
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it, and forking a branch ACAB off of branch AC and then merging AB
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into it, would yield the conflict in a different order. The former
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would say "A became B or C, what now?" while the latter would say "A
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became C or B, what now?"
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As a reminder, the act of merging AC into ABAC and resolving the
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conflict to leave line D means that the user declares:
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After examining what branches AB and AC did, I believe that
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making line A into line D is the best thing to do that is
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compatible with what AB and AC wanted to do.
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So the conflict we would see when merging AB into ACAB should be
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resolved the same way---it is the resolution that is in line with that
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declaration.
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Imagine that similarly previously a branch XYXZ was forked from XY,
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and XZ was merged into it, and resolved "X became Y or Z" into "X
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became W".
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Now, if a branch ABXY was forked from AB and then merged XY, then ABXY
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would have line B in its early part and line Y in its later part.
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Such a merge would be quite clean. We can construct 4 combinations
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using these four branches ((AB, AC) x (XY, XZ)).
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Merging ABXY and ACXZ would make "an early A became B or C, a late X
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became Y or Z" conflict, while merging ACXY and ABXZ would make "an
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early A became C or B, a late X became Y or Z". We can see there are
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4 combinations of ("B or C", "C or B") x ("X or Y", "Y or X").
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By sorting, the conflict is given its canonical name, namely, "an
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2020-11-21 19:20:35 +01:00
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early part became B or C, a late part became X or Y", and whenever
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2020-01-12 00:36:56 +01:00
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any of these four patterns appear, and we can get to the same conflict
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and resolution that we saw earlier.
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Without the sorting, we'd have to somehow find a previous resolution
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from combinatorial explosion.
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Conflict ID calculation
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~~~~~~~~~~~~~~~~~~~~~~~
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Once the conflict normalization is done, the conflict ID is calculated
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as the sha1 hash of the conflict hunks appended to each other,
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separated by <NUL> characters. The conflict markers are stripped out
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before the sha1 is calculated. So in the example above, where we
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merge branch AC which changes line A to line C, into branch AB, which
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changes line A to line C, the conflict ID would be
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SHA1('B<NUL>C<NUL>').
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If there are multiple conflicts in one file, the sha1 is calculated
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the same way with all hunks appended to each other, in the order in
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which they appear in the file, separated by a <NUL> character.
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Nested conflicts
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~~~~~~~~~~~~~~~~
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Nested conflicts are handled very similarly to "simple" conflicts.
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Similar to simple conflicts, the conflict is first normalized by
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stripping the labels from conflict markers, stripping the common ancestor
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version, and the sorting the conflict hunks, both for the outer and the
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inner conflict. This is done recursively, so any number of nested
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conflicts can be handled.
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Note that this only works for conflict markers that "cleanly nest". If
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there are any unmatched conflict markers, rerere will fail to handle
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the conflict and record a conflict resolution.
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The only difference is in how the conflict ID is calculated. For the
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inner conflict, the conflict markers themselves are not stripped out
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before calculating the sha1.
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Say we have the following conflict for example:
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<<<<<<< HEAD
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1
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=======
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<<<<<<< HEAD
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3
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=======
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2
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>>>>>>> branch-2
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>>>>>>> branch-3~
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After stripping out the labels of the conflict markers, and sorting
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the hunks, the conflict would look as follows:
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<<<<<<<
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1
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=======
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<<<<<<<
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2
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=======
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3
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>>>>>>>
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>>>>>>>
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and finally the conflict ID would be calculated as:
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`sha1('1<NUL><<<<<<<\n3\n=======\n2\n>>>>>>><NUL>')`
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