48 lines
2.3 KiB
Ruby
48 lines
2.3 KiB
Ruby
RSpec.describe ExpertsProcedure, type: :model do
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describe '#invited_expert_emails' do
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let!(:procedure) { create(:procedure, :published) }
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let(:expert) { create(:expert) }
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let(:expert2) { create(:expert) }
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let(:expert3) { create(:expert) }
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let(:experts_procedure) { ExpertsProcedure.create(expert: expert, procedure: procedure) }
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let(:experts_procedure2) { ExpertsProcedure.create(expert: expert2, procedure: procedure) }
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let(:experts_procedure3) { ExpertsProcedure.create(expert: expert3, procedure: procedure) }
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subject { procedure.experts_procedures }
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context 'when there is one dossier' do
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let!(:dossier) { create(:dossier, procedure: procedure) }
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context 'when a procedure has one avis and known instructeur' do
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let!(:avis) { create(:avis, dossier: dossier, instructeur: create(:instructeur, email: expert.email), experts_procedure: experts_procedure) }
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it { is_expected.to eq([experts_procedure]) }
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it { expect(procedure.experts.count).to eq(1) }
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it { expect(procedure.experts.first.email).to eq(expert.email) }
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end
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context 'when a dossier has 2 avis from the same expert' do
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let!(:avis) { create(:avis, dossier: dossier, experts_procedure: experts_procedure) }
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let!(:avis2) { create(:avis, dossier: dossier, experts_procedure: experts_procedure) }
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it { is_expected.to eq([experts_procedure]) }
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it { expect(procedure.experts.count).to eq(1) }
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it { expect(procedure.experts.first).to eq(expert) }
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end
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end
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context 'when there are two dossiers' do
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let!(:dossier) { create(:dossier, procedure: procedure) }
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let!(:dossier2) { create(:dossier, procedure: procedure) }
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context 'and each one has an avis from 3 different experts' do
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let!(:avis) { create(:avis, dossier: dossier, experts_procedure: experts_procedure) }
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let!(:avis2) { create(:avis, dossier: dossier2, experts_procedure: experts_procedure2) }
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let!(:avis3) { create(:avis, dossier: dossier2, experts_procedure: experts_procedure3) }
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it { is_expected.to match_array([experts_procedure, experts_procedure2, experts_procedure3]) }
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it { expect(procedure.experts.count).to eq(3) }
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it { expect(procedure.experts).to match_array([expert, expert2, expert3]) }
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end
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end
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end
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end
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